We’re now going to learn a

little bit about gravity. And just so you know, gravity is

something that, especially in introductory physics or

even reasonably advanced physics, we can learn how to

calculate it, we can learn how to realize what are the

important variables in it, but it’s something that’s really

not well understood. Even once you learn general

relativity, if you do get there, I have to say, you can

kind of say, oh, well, it’s the warping of space time and

all of this, but it’s hard to get an intuition of why two

objects, just because they have this thing called

mass, they are attracted to each other. It’s really, at least to me,

a little bit mystical. But with that said, let’s learn

to deal with gravity. And we’ll do that learning

Newton’s Law of Gravity, and this works for most purposes. So Newton’s Law of Gravity says

that the force between two masses, and that’s the

gravitational force, is equal to the gravitational constant G

times the mass of the first object times the mass of the

second object divided by the distance between the two

objects squared. So that’s simple enough. So let’s play around with this,

and see if we can get some results that look

reasonably familiar to us. So let’s use this formula

to figure out what the acceleration, the gravitational

acceleration, is at the surface of the Earth. So let’s draw the Earth,

just so we know what we’re talking about. So that’s my Earth. And let’s say we want to figure

out the gravitational acceleration on Sal. That’s me. And so how do we apply this

equation to figure out how much I’m accelerating down

towards the center of Earth or the Earth’s center of mass? The force is equal to– so

what’s this big G thing? The G is the universal

gravitational constant. Although, as far as I know, and

I’m not an expert on this, I actually think its measurement

can change. It’s not truly, truly a

constant, or I guess when on different scales, it can be

a little bit different. But for our purposes, it is a

constant, and the constant in most physics classes, is this:

6.67 times 10 to the negative 11th meters cubed per kilogram

seconds squared. I know these units are crazy,

but all you have to realize is these are just the units needed,

that when you multiply it times a mass and a mass

divided by a distance squared, you get Newtons, or kilogram

meters per second squared. So we won’t worry so much about

the units right now. Just realize that you’re going

to have to work with meters in kilograms seconds. So let’s just write

that number down. I’ll change colors to

keep it interesting. 6.67 times 10 to the negative

11th, and we want to know the acceleration on Sal, so

m1 is the mass of Sal. And I don’t feel like revealing

my mass in this video, so I’ll just leave

it as a variable. And then what’s the mass 2? It’s the mass of Earth. And I wrote that here. I looked it up on Wikipedia. This is the mass of Earth. So I multiply it times the

mass of Earth, times 5.97 times 10 to the 24th kilograms–

weighs a little bit, not weighs, is a little

bit more massive than Sal– divided by the distance

squared. Now, you might say, well, what’s

the distance between someone standing on the

Earth and the Earth? Well, it’s zero because they’re

touching the Earth. But it’s important to realize

that the distance between the two objects, especially when

we’re talking about the universal law of gravitation, is

the distance between their center of masses. For all general purposes, my

center of mass, maybe it’s like three feet above

the ground, because I’m not that tall. It’s probably a little bit lower

than that, actually. Anyway, my center of mass might

be three feet above the ground, and where’s Earth’s

center of mass? Well, it’s at the center of

Earth, so we have to know the radius of Earth, right? So the radius of Earth is–

I also looked it up on Wikipedia– 6,371 kilometers. How many meters is that? It’s 6 million meters, right? And then, you know, the extra

meter to get to my center of mass, we can ignore for now,

because it would be .001, so we’ll ignore that for now. So it’s 6– and soon. I’ll write it in scientific

notation since everything else is in scientific notation–

6.371 times 10 to the sixth meters, right? 6,000 kilometers is

6 million meters. So let’s write that down. So the distance is going

to be 6.37 times 10 to the sixth meters. We have to square that. Remember, it’s distance

squared. So let’s see if we can simplify

this a little bit. Let’s just multiply those top

numbers first. Force is equal to– let’s bring the

variable out. Mass of Sal times– let’s

do this top part. So we have 6.67 times 5.97

is equal to 39.82. And I just multiplied this times

this, so now I have to multiply the 10’s. So 10 to the negative 11th times

10 to the negative 24th. We can just add the exponents. They have the same base. So what’s 24 minus 11? It’s 10 to the 13th, right? And then what does the

denominator look like? It’s going to be the 6.37

squared times 10 to the sixth squared. So it’s going to be– whatever

this is is going to be like 37 or something– times– what’s

10 to the sixth squared? It’s 10 to the 12th, right? 10 to the 12th. So let’s figure out what

6.37 squared is. This little calculator I have

doesn’t have squared, so I have to– so it’s 40.58. And so simplifying it, the force

is equal to the mass of Sal times– let’s divide, 39.82

divided by 40.58 is equal to 9.81. That’s just this divided

by this. And then 10 to the 13th divided

by 10 to the 12th. Actually no, this isn’t 9.81. Sorry, it’s 0.981. 0.981, and then 10 to the 13th

divided by 10 to the 12th is just 10, right? 10 to the first, times 10,

so what’s 0.981 times 10? Well, the force is equal to 9.81

times the mass of Sal. And where does this get us? How can we figure out the

acceleration right now? Well, force is just mass times

acceleration, right? So that’s also going to just be

equal to the acceleration of gravity– that’s supposed to

be a small g there– times the mass of Sal, right? So we know the gravitational

force is 9.81 times the mass of Sal, and we also know that

that’s the same thing as the acceleration of gravity

times the mass of Sal. We can divide both sides by the

mass of Sal, and we have the acceleration of gravity. And if we had used the units the

whole way, you would have seen that it is kilograms meters

per second squared. And we have just shown that, at

least based on the numbers that they’ve given in Wikipedia,

the acceleration of gravity on the surface of the

Earth is almost exactly what we’ve been using in all the

projectile motion problems. It’s 9.8 meters per

second squared. That’s exciting. So let’s do another quick

problem with gravity, because I’ve got two minutes. Let’s say there’s another

planet called the planet Small Earth. And let’s say the radius of

Small Earth is equal to 1/2 the radius of Earth and the mass

of Small Earth is equal to 1/2 the mass of Earth. So what’s the pull of gravity

on any object, say same object, on this? How much smaller would

it be on this planet? Well, actually let me save

that to the next video, because I hate being rushed. So I’ll see you